Question

Mr. Bhulakkar forgot his ATM password which is
a four-digit number. However, he remembered that
the first two digits (the left most digit is the first digit)
of the password formed a two-digit number divisible
by 12 and that the first and the fourth digits, when
placed together, formed the cube of a natural
number. If the password itself was a number divisible
by 11, the sum of whose digits was odd, find the
password​

Answer 1

Answer:

6094

Step-by-step explanation:

12,24,36,48,60,72,84,96 fits into numbers divisible by 12

1st and 4th digit placed together formed a cube so can be

3^3 or 4^3 ,  

so it can be 24_7 or 60_4

4 digits should be divisible by 11 so we may get 2497 or 6094

sum of the digits is odd so

2+4+9+7=22(even)

6+0+9+4=19(odd)