Mr. Bose gave 2/3 of his wife. His wife gave 3/4 of her money to her daughter. Two thirds of the daughter’s money was stolen and she was left with rs30000. How much money did Mr. Bose have?
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Here is the solution:
Let the Mr. boss's total money be x.
As per the question,
Mr. boss gave his wife = 2/3 of x = 2x/3
His wife gave her daughter=3/4 of 2x/3
=3/4*2x/3
= x/2
Money stolen= 2/3 of x/2
= 2/3*x/2
= x/3
Money left with his daughter = x/2-x/3
= x/6.
Also money left =30,000.
So, x/6=30000
=>x= 30000×6
=>x=1, 80,000Rs.
Therefore, answer Mr.boss had 180000Rs.
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