Question

Mr. doshi twice as old as his son at present. after ten years, the ratio of their ages would be 5:3. what is the age of his son at present?

Answer 1

Let age od doshi be "d" and his son's age be "s"

Given doshi twice as old as his son at present i.e., d=2s------------>1

Also given after ten years, the ratio of their ages would be 5:3 i.e.,

(d+10)/(s+10)=5/3--------->2

from 1 and 2 we get s=20 which is persent age of son and d=40 which is present age of doshi.

Answer 2

Answer:

Mr. Doshi is 40 years old and his son is 20 years old.

Step-by-step explanation:

Given :

Mr.Doshi = twice as old as his son

After 10 years ratio of their ages = 5 : 3

To find :

Present age of the son

Solution :

Let the present ages be -

• Son as x
• Mr. Doshi as 2x

$\sf{\longrightarrow} \: \frac{2x + 10}{x + 10} = \frac{5}{3} \\ \\ \sf{\longrightarrow} \: 3(2x + 10) = 5(x + 10) \\ \\ \sf{\longrightarrow} \: 6x + 30 = 5x + 50 \\ \\ \sf{\longrightarrow} \: 6x - 5x = 50 - 30 \\ \\ \sf{\longrightarrow} \: x = 20$

Son = 20 years old

$\rule{300}{1.5}$

★ Value of 2x

$\sf{\longrightarrow} \: 2(20) \\ \\ \sf{\longrightarrow} \: 40$

Mr. Doshi = 40 years old

$\therefore$ Mr. Doshi is 40 years old and his son is 20 years old.