Mr Grover is three times as old as his son and the sum of their ages is 48 how old is each?
Answers
Let mr grover and his son age = x
And his age be 3x
ATQ
3x+x=48
4x+48
X=48/4=12
Age of son = 12 years
Age of mr grover = 3x
=3(12)
=36 years
Age of mr grover = 36 years
Hope it will help you
Mr.Grover's age is 36 years and his son's age is 12 years
Step-by-step explanation:
Given:
Mr. Grover is three times as old as his son
the sum of their ages is 48
To find:
age of Mr.Grover and his son
Solution:
Let's assume Mr.Grover's age is x years and his son's age is y years
According to the given
Mr.Grover's age (x) is 3times (3) old as his son's age (y)
x= 3y
Forming a linear equation
x-3y=0..........(i)
Now, the sum of their ages (x+y) is given as 48
∴ x+y=48......(ii)
We solve both the linear equations using the elimination method
Subtracting equation (i) from (ii) we get
x + y= 48
x - 3y= 0
(-) (+) (-)
4y= 48........................(adding the like terms and eliminating x)
∴ 4y =48
∴ y= 48/4
∴ y= 12
Thus, Mr.Grover's son's age is 12 years
So his age will be
x+y=48
∴ x+12=48
∴ x= 48-12
∴ x= 36
Finally, Mr.Grover's age will be 36 years
Hence, Mr.Grover is 36 years old and his son is 12 years old
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