Question

Mr. John, bought two varieties of wine at Rs. 200 per litre and Rs. 260 per litre respectively. He mixed them in some proportion and then added 12 litres of
water per 100 litres of this mixture to get a new wine. He sold this new wine at Rs. 250 per litre, thereby making a profit of 25%. How many litres of the Rs. 260
per litre variant of wine has Mr. John added in 112 litres of the new wine?
А​

Answer 1

Solution :-

given that,

→ Selling Price of new wine = Rs.250/litre

→ Profit = 25%.

so,

→ CP of new wine = (SP * 100) / (100 + Profit%) = (250 * 100) / (100 + 25) = (250 * 100)/125 = Rs.200/litre.

Now, Let us assume that, x litres of wine costing Rs.260 was added in 112 litres of the new wine.

also given that, 12 litres of water per 100 litres of this mixture was added to get a new wine .

So,

• Total mixture = 100 litre.
• Quantity of wine costing Rs.260/litre = x litre .
• Quantity of wine costing Rs.200/litre = (100 - x) litre

then,

→ Total CP of 112 litres of the new wine = CP of x litres of wine at Rs.260/litre + CP of (100 - x) litres of wine at Rs.200/litre

→ 200 * 112 = 260 * x + 200(100 - x)

→ 22400 = 260x + 20000 - 200x

→ 60x = 22400 - 20000

→ 60x = 2400

→ x = 40 Litre (Ans.)

Hence, 40 Litres of Rs. 260/litre variant of wine has Mr. John added in 112 litres of the new wine .

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