Mr kasam runs a small business of making earthen pots he makes certain number of pots on daily basis production cost of each pot is rs40 more than 10 times total number of pots he make in a day if production cost of all pots per day is rs 600find production cost of one pot and number of pots and number of pots he makes per day
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Here is the answer
Let Kasam makes 'x' eathen pots per day .
Then the cost of each earthen pots is Rs.(10x + 40 )
From the given condition,
x(10x + 40) = 600
Therefore,
10x^2 +40x - 600 = 0
Dividing by 10 ,
x^2 + 4x - 60 = 0
x^2 + 10x - 6x - 60 = 0
x(x + 10) - 6(x + 10) = 0
(x - 6)(x + 10) = 0
x = -10 or x = 6
But the number of earthen pots cannot be negative.
So, x = -10 is not acceptable.
So,
x = 6
The cost of each earthen pots
= 10x + 40
= 10(6) + 40
= 60 + 40
= 100
Final answer
He makes 6 earthen pots per day and cost of each earthen pots is Rs 100
Let Kasam makes 'x' eathen pots per day .
Then the cost of each earthen pots is Rs.(10x + 40 )
From the given condition,
x(10x + 40) = 600
Therefore,
10x^2 +40x - 600 = 0
Dividing by 10 ,
x^2 + 4x - 60 = 0
x^2 + 10x - 6x - 60 = 0
x(x + 10) - 6(x + 10) = 0
(x - 6)(x + 10) = 0
x = -10 or x = 6
But the number of earthen pots cannot be negative.
So, x = -10 is not acceptable.
So,
x = 6
The cost of each earthen pots
= 10x + 40
= 10(6) + 40
= 60 + 40
= 100
Final answer
He makes 6 earthen pots per day and cost of each earthen pots is Rs 100
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