Question

Mr.Marci Juan, a bakeshop owner, sells chocolate cakes.He divides a whole retangular chocolate into 16 equal parts and sells each part for 50 pesos.If he's able to sell 1/4 of the whole cake to a customer and another two slices to another customer'

(A) How much is the cost of the whole cake?
(B) What is the amount of his sales from his two customers?
please answer this​

Answer 1

Answer:

(A) 800 pesos

(B) 200 pesos, 100 pesos

Step-by-step explanation:

Cost of each slice (1/16 of the cake) = 50 pesos (given)

The cost of the whole cake = 16 * 50 = 800 pesos

Amount of sales from the first customer = 1/4 * 800 = 200 pesos

Amount of sales from the second customer = 2 * 50 = 100 pesos

Hence, the total cost of the cake is 800 pesos and he made 200 and 100

pesos respectively with his two customers.

Answer 2

Given: Total number of parts the chocolate cake is divided in = 16.

The cost of each part = 50 pesos.

The owner sells 1/4 of the whole cake to a customer and another two slices to another customer.

To find: (A) How much is the cost of the whole cake?

(B) What is the amount of his sales from his two customers?

Solution:

(A) The cost of the whole cake

= number of pieces of chocolate cake × cost of each part

= 16 × 50 pesos

= 800 pesos.

(B) Number of parts sold to the first customer = 1/4 × 16 = 4

Amount of sales from the first customer = 4 × 50 pesos = 200 pesos.

Amount of sales from the second customer = 2 × 50 pesos = 100 pesos.

Therefore, total amount of the owner's sales from the two customers

= (200 + 100) pesos

= 300 pesos.

Answer: (A) 800 pesos

(B) 300 pesos