Mr. Pandey has a square plot with the neasurernent as shown in the given fqure. He wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing the garden around the house at the rate of 40 per m²?
Answers
Answer:
356
Step-by-step explanation:
1. In quadrilateral ACBD, AC = AD and AB bisects ∠A )see figure). Show that ΔABC ≌ ΔABD. What can you say about BC and BD?

Ans. In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.
2. ABCD is a quadrilateral in which AD = BC and ∠DAB = ∠CBA (see Figure). Prove that
(i) ΔABD ≌ ΔBAC
(ii) BD = AC
(iii) ∠ABD = ∠BAC.

Answer:
Therefore, Area of the house = length x breadth = 20 x 15 = 300 m2 Area of garden = Area of square plot – Area of house = 625 – 300 = 325 m2 Cost of developing the garden per sq. m = ₹ 55 Therefore, Cost of developing the garden 325 sq. m = ₹ 55 x 325 = ₹ 17,875 Hence total cost of developing a garden around is ₹ 17,875.Read more on Sarthaks.com - https://www.sarthaks.com/17720/kaushik-square-plot-with-measurement-shown-the-figure-wants-construct-house-middle-plot