Math, asked by swarnar12345, 11 months ago

Mr.Ram borrows Rs20000 compounded annually.The rate of interest for two successive years are 9% and 10% respectively.If he repays Rs1200 at the end of the first year. Rs 1660 at the end of the second year.​

Answers

Answered by bhanusreenivasan650
2

Answer:

ill send the pic

Step-by-step explanation:

he gives 582 rs extra

lol!!

Attachments:
Answered by amitnrw
0

Given : Mr.Ram borrows Rs20000 compounded annually. rate of interest for two successive years are 9% and 10% respectively.

To find : Balance Amount remaining after 2 Years

Solution:

P = 20000

R = 9 %

Interest for 1st year = 20000 * 9 * 1 /100 = Rs 1800

Amount Paid = Rs 1200

Amount remain  after 1 year = 20000 + 1800 - 1200

= 20600 Rs

Interest for 2nd Year = 20600 * 10 * 1 /100

= Rs 2060

Paid at 2nd year  = Rs 1660

Interest Paid Less = 2060 - 1660

= Rs 400

Amount Balance after 2 year = 20600 + 400

= Rs 21000

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