Math, asked by angel2249, 3 days ago

Mr. Raman gave 1 6 of his property to his son, 1 4 to his daughter and the remaining to his wife. If the total property was worth Rs. 2,40,000 find
a) Amount of son’s share
b) Amount of wife’s share
who knows answers only other will answer other will reported
and ya its right question so who knows only they will answer​

Answers

Answered by james7389
1

a)40,000

b)140000

Answer:

lets calculate sons propert first which is 1 /6

 \frac{1}{6} of \: 240000 \\  =  \frac{1}{6}  \times 240000 \\  =  \frac{1 \times 240000}{6}  \\  =  \frac{240000}{6}  \\  =  \frac{40000}{1}  = 40000rupees

lets calculate daughters property

 \frac{1}{4} of 240000 \\  =  \frac{1}{4}  \times 240000 \\  =  \frac{1 \times 240000}{4}  \\  =  \frac{240000}{4}   \\  =  \frac{60000}{1}  = 60000rupees

lets calculate total property received by his children

60000 + 40000 = 100000rupees

his totsl property was Rs. 2,40,000.

now it says that after giving money to his children leftovers was of wife. so to find leftover we need to subtract lets do it.

240000 - 100000 = 140,000rupees

the leftover propert of wife is 140,000 rupees

Answered by shifatkhan9378
0

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