Math, asked by snehasharma47, 1 year ago

mr. sharma bought a land of length 60m and width 15m . If each side of this land is to be fenced with 8 rows of wires . find:
a) length of the wire required to do so?
b) find the cost of fencing at the rate of Rs. 18.85 per metre.

Answers

Answered by soundrarajanksr27
0
Length of wire required= 8(2(60+15))m
= 16(75)m
=1200 m
cost of fencing = 1200×18.85 Rs.

=Rs. 22620
Answered by Anonymous
9
Solutions :-

Given :
Length = 60 m
Breadth = 15 m

Find the perimeter of land :-

Perimeter of rectangle = 2(Length + Breadth)
= 2(60 + 15)
= 2 × 75
= 150 m

Given :
Each side of this land is to be fenced with 8 rows of wires.

Find the Length of the wire required to do so :-

1 row of wires = 150 m
8 rows of wires = 150 × 8 = 1200 m

Find the the cost of fencing at the rate of Rs. 18.85 per metre :-

1 m = Rs 18.85
1200 m = Rs 18.85 × 1200 = Rs 22620

Hence,
a) Length of the wire required to do so = 1200 m

b) The cost of fencing at the rate of Rs. 18.85 per metre = Rs 22620

_______________________

✯ @shivamsinghamrajput ✯

Anonymous: thanks :)
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