Question

Mr Smith has a bag A. Bag A has "n" numbers of bag B. Each bag B has " n " numbers of bag C. Each bag C has " n" number of one rupee coins in it. If one bag B is removed from bag A, then the total number of coins left in bag A is.....

Answer 1

answer is n^3

solution:

Total number of one rupee coins in bag C = n

one B bag has 'n' C bags , so one B bag has   n x n coins

one A bag has 'n' B bags, So total coins in bag A = n x n xn = n^3 coins