Question

Mr. thomas invested an amount of rs. 13,900 divided in two different schemes a and b at the simple interest rate of 14% p.a. and 11% p.a. respectively. if the total amount of simple interest earned in 2 years be rs. 3508, what was the amount invested in scheme b? calculate simple intrest

Answer 1

13900×11×2/2×100
=1529



13900×11×2/2×100 = 1529, 1529×100/11×2 = 6950

Answer 2

Step-by-step explanation:

Given :  Invested Amount  Rs 13900 divided in 2 different schemes A and B at SI 14% pa and 11% pa

Total amount of SI earned in 2years = 3058

To Find : Amount invested in Scheme B

Solution:

Let say Amount invested in Scheme B  = 100P

Amount invested in Scheme A  = 13900 - 100P

= 100(139 - P)

SI = P x R x T /100

invested in Scheme A  =100(139 - P)

R = 14%

T = 2

SI = 100(139 - P) * 14 * 2 /100

= (139 - P)28

= 3892 - 28P

invested in Scheme B  =100P

R = 11%

T = 2

SI = 100P  * 11 * 2 /100

=22P

3892 - 28P + 22P =  3508

=> 3892 - 6P =  3508

=> 6P =  384

=> P = 64

=> 100P = 6400

Amount invested in Scheme B = Rs 6400