Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
A.Rs. 6400
B.Rs. 6500
C.Rs. 7200
D.Rs. 7500
Answers
Answered by
4
ĀNSWĒR ⏬⏬
A Rs .6400
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then,x x 14 x 2+(13900 - x) x 11 x 2
= 350810010
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
THANKS ✌✌
A Rs .6400
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then,x x 14 x 2+(13900 - x) x 11 x 2
= 350810010
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
THANKS ✌✌
Answered by
3
______✨ HEY MATE ✨______
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SOLUTION :-
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Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then,{x x 14 x 2}+{(13900 - x) x 11 x 2}= 3508100100
=> 28x - 22x = 350800 - (13900 x 22)
=> 6x = 45000
=> x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
So , Option (A) Rs. 6400 is the right answer ✔️
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SOLUTION :-
=============
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then,{x x 14 x 2}+{(13900 - x) x 11 x 2}= 3508100100
=> 28x - 22x = 350800 - (13900 x 22)
=> 6x = 45000
=> x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
So , Option (A) Rs. 6400 is the right answer ✔️
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