Math, asked by parul3867, 1 year ago

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
A.Rs. 6400
B.Rs. 6500
C.Rs. 7200
D.Rs. 7500

Answers

Answered by Anonymous
4
ĀNSWĒR ⏬⏬

A Rs .6400


Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then,x x 14 x 2+(13900 - x) x 11 x 2
= 350810010

 28x - 22x = 350800 - (13900 x 22)

6x = 45000

 x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.


THANKS ✌✌
Answered by Anonymous
3
______✨ HEY MATE ✨______

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SOLUTION :-
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Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).

Then,{x x 14 x 2}+{(13900 - x) x 11 x 2}= 3508100100

=> 28x - 22x = 350800 - (13900 x 22)

=> 6x = 45000

=>  x = 7500.

So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.

So , Option (A) Rs. 6400 is the right answer ✔️

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