Math, asked by shrutikjadhav007, 10 months ago

mr valia invested some money at a certain rate of simple interest per annum. The total amounts received by him were rs.7654.4 in 2 years and rs.7948.8 in 4 years respectively. Find principal and the rate of simple interest.

Answers

Answered by acesolution2017
0

Answer:

Step-by-step explanation:

Simple Interest is given as = PRT/100;

Here P = Principal Amount, R = Rate of interest, T = Time;

Total amount after certain year  = P + PRT/100

7654.4 = P + PR*2/100; Eq. 1;

7948.8 = P + PR*4/100; Eq. 2;

Now solving both the equations

7654.4 = P + 0.02PR:

7948.8 = P + 0.04PR;

Now Eq. 1 - Eq. 2;

294.4 = PR*2/100;

14720 = PR;

Putting this value in 7654.4 = P + 0.02PR;

7654.4 = P + 0.02*14720;

P = 7654.4 - 294.4

P = 7360;

Not putting this value in 14720 = PR;

we get ;

R = 14720/7360

R = 2

Answered by amitnrw
3

Answer:

Step-by-step explanation:

Simple Interest = P * R * T/100

P = principle Rs

R = Rate of interest per annum

T = time period of investment in Years

Interest in two years =  P * R * 2 /100

Interest in 4 Years = P * R * 4/100

Interest of two years = Interest of 4 years - Interest of two years

4PR/100 - 2PR/100 = 2PR/100  ( interest from 2 to 4 years = interest from 2 Years)

7948.8 -  7654.4 = 2PR/100  ( Amount from 4th year - amount from 2nd Year)

=> 2PR/100 = 294.4

7654.4 = P + 2PR/100   ( amount received after 2 years)

=>  7654.4 = P + 294.4

=> P = 7360 Rs

2 * 7360 R /100 = 294.4

=> R = 2944/(2 * 736)

=> R = 2 % per annum

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