Mr.Verma has an orchard of length and breadth 280m and 200m respectively. He wants to fence it with 4 rounds of barbed wire. Find the cost of fencing at ₹35 per metre.
Answers
Answered by
24
L=280m
B=200m
perimeter=2(l+b)
=2(280+200)
=2×480
=960m
So
for four round=960m×4
=3840m
AS per the question
1m= Rs35
3840m=(?)
So 3840m×35
Ans= Rs 1,34,400
B=200m
perimeter=2(l+b)
=2(280+200)
=2×480
=960m
So
for four round=960m×4
=3840m
AS per the question
1m= Rs35
3840m=(?)
So 3840m×35
Ans= Rs 1,34,400
Answered by
12
The cost of fencing at ₹35 per metre is Rs.33600
Step-by-step explanation:
Length of orchard = 280 m
Breadth of orchard = 200 m
Perimeter of orchard = 2(l+b)=2(280+200)=960 m
Cost of fencing 1 m = Rs.35
Cost of fencing 960 m =
Hence the cost of fencing at ₹35 per metre is Rs.33600
#Learn more:
Farmer has a rectangular field of length 240 metre and breadth 150 respectively he wants to fence it with three rounds of rope as shown in the adjoining figure if the Rope costs rupees 4 then find the cost of fencing the field
https://brainly.in/question/15183500
Similar questions