Question

Mr.X and mr.Y enter in to a railway compartment having six vacant seats. The number of ways in which they can occupy the seats is ?

Answer 1

$\underline{\textbf{Given:}}$

$\textsf{Mr. X and Mr. Y enter into a railway compartment}$

$\textsf{having six seats}$

$\underline{\textbf{To find:}}$

$\textsf{The number of ways in which they can occupy the seats}$

$\underline{\textbf{Solution:}}$

$\textsf{Since there are 6 seats,}$

$\textsf{X can occupy any one of the seat in 6 ways}$

$\textsf{Y can occupy the remaining 5 seats in 5 ways }$

$\textsf{By fndamental principle of multiplication,}$

$\textsf{Total number of ways they can occupy the seats}$

$\mathsf{=6{\times}5}$

$\mathsf{=30\;ways}$

Answer 2

Step-by-step explanation:

\underline{\textbf{Given:}}Given:

\textsf{Mr. X and Mr. Y enter into a railway compartment}Mr. X and Mr. Y enter into a railway compartment

\textsf{having six seats}having six seats

\underline{\textbf{To find:}}To find:

\textsf{The number of ways in which they can occupy the seats}The number of ways in which they can occupy the seats

\underline{\textbf{Solution:}}Solution:

\textsf{Since there are 6 seats,}Since there are 6 seats,

\textsf{X can occupy any one of the seat in 6 ways}X can occupy any one of the seat in 6 ways

\textsf{Y can occupy the remaining 5 seats in 5 ways }Y can occupy the remaining 5 seats in 5 ways 

\textsf{By fndamental principle of multiplication,}By fndamental principle of multiplication,

\textsf{Total number of ways they can occupy the seats}Total number of ways they can occupy the seats

\mathsf{=6{\times}5}=6×5

\mathsf{=30\;ways}=30ways