Mr.x is twice his daughters present age. how many years ago was he three times his daughters age if his daughter present age is 20.
Answers
Answer:
let mr.x age be a
a = 2(20)
a=40 ------ (1)
ages before b years
a-b=3(20-b)
a-b=60-3b
a=60-3b+b
a=60-2b
put a=40
40=60-2b
2b=60-40
2b=20
b=10
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Answer:
6 years and 8 months ago fathers age is 3 times the that of daughter's age
Step-by-step explanation:
Given data
Mr.x is twice his daughter present age
His daughter's present age = 20
here we need to find when was the fathers age is three times of his daughter's age
from given data fathers present age = 2(daughter's age) = 2(20) = 40
let before x years fathers age is three times of his daughter's age
⇒ age father x years ago = 40 - x
⇒ daughter's age = 20 - x
⇒ (40 - x) = 3 (20 - x)
⇒ 40 - x = 60 - 3x
⇒ 3x = 20
⇒ x = 6 (2/3) years
⇒ 6 years and 8 months ago fathers age is 3 times the that of daughter's age