mrs. Gupta repays her total loan of rupees 1,18,000 by paying installment every month if the installment for the first month is rupees 1000 and it increases by 100 every month what amount will she pay as the 30th installment of the loan ?what amount of loan she still has to pay after 30th installment
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Step-by-step explanation:
Total loan amount = 118000;
Installments are increases like 1000, 1100,1200,1300...... Total n = 30 installments!;
Common difference (d) = 100;
Initial term = 1000;
Formula of addition of n terms;
Sum = n/2[2a+(n-1)d];
= (30/2) [2*1000+(30-1)100];
= 15(2000+2900);
= 15(4900)
= 73500 Total amount paid in 30 installments;
Amount have to be paid after 30 installments = 118000-73500 = 44500;
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