MRS Jain is 27 years older than her daughter n she will be twice as old as Neetu find their present age.
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Answered by
1
Step-by-step explanation:
Let Nilu's present age be x yrs. So , Her mother age = x+27 yrs. So , Nilu's Age = x =19 yrs. Her mother = 19+27= 46 yrs .
Answered by
2
Let the present age of Nilu be x years
Therefore the present age of Nilu’s mother = (x + 27) years
So, after 8 years, Nilu’s age = (x + 8)
and Mrs Jain’s age = (x + 27 + 8) = (x + 35) years
⇒ x + 35 = 2(x + 8)
Expanding the brackets, we get
⇒ x + 35 = 2x + 16
Transposing x to RHS and 16 to LHS, we get
⇒ 35 – 16 = 2x – x
⇒ x = 19
So, the present age of Nilu = x = 19 years
And the present age of Nilu’s mother that is Mrs Jain = x+ 27 = 19 + 27
= 46 years
THEREFORE,
Nilu's age = 19 years
Mrs Jain = 46 years
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