Math, asked by himanshidubey66, 8 months ago

MRS Jain is 27 years older than her daughter n she will be twice as old as Neetu find their present age.​

Answers

Answered by Sevyasahasra
1

Step-by-step explanation:

Let Nilu's present age be x yrs. So , Her mother age = x+27 yrs. So , Nilu's Age = x =19 yrs. Her mother = 19+27= 46 yrs .

Answered by Anonymous
2

Let the present age of Nilu be x years

Therefore the present age of Nilu’s mother = (x + 27) years

So, after 8 years, Nilu’s age = (x + 8)

and Mrs Jain’s age = (x + 27 + 8) = (x + 35) years

⇒ x + 35 = 2(x + 8)

Expanding the brackets, we get

⇒ x + 35 = 2x + 16

Transposing x to RHS and 16 to LHS, we get

⇒ 35 – 16 = 2x – x

⇒ x = 19

So, the present age of Nilu = x = 19 years

And the present age of Nilu’s mother that is Mrs Jain = x+ 27 = 19 + 27

= 46 years

THEREFORE,

Nilu's age = 19 years

Mrs Jain = 46 years

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