Mrs. Jain is 27 years older than her daughter nilu. After 8 years she will be as old as nilu. Find their present ages
Answers
Correct Question :–
Mrs. Jain is 27 years older than her daughter Nilu. After 8 years she will be twice as old as Nilu. Find their present ages.
Answer :–
- The present age of Nilu = 19 years.
- The present age of Mrs. Jain = 46 years.
Given :–
- Mrs. Jain is 27 years older than her daughter Nilu.
- After 8 years she will be as old as Nilu.
To Find :–
- Present ages of both Mrs. Jain and her daughter Nilu.
Solution :–
Let,
• The Nilu's present age be x.
Her mother is 27 years older than Nilu.
So,
• Her mother's present age be x + 27.
After 8 years,
• Nilu's age = x + 8.
• Her mother's age = x + 27 + 8 = x + 35
According to the question,
After 8 years she will be twice as old as Nilu.
So,
→ x + 35 = 2(x + 8)
Now, open the bracket.
→ x + 35 = 2x + 16
→ 35 – 16 = 2x – x
→ 19 = 1x
→ x = 19
Hence,
The present age of Nilu = 19 years.
The present age of her mother Mrs. Jain = x + 27 = 19 + 27 = 46 years.
Correct Question:
Mrs. Jain is 27 years older than her daughter nilu. After 8 years she will be twice as old as nilu. Find their present ages.
Step-by-step explanation:
Let the present age of Nilu be x years.
★Given that, Mrs. Jain is 27 years older than her daughter Nilu.
Then,
- Present age of Mrs. Jain = (x+27) years.
After 8 years,
- Age of Nilu = (x+8) years
- Age of Mrs. Jain = (x+27+8) = (x+35) years
According to the question,
2(x+8) = (x+35)
→ 2x+16 = x+35
→ 2x-x = 35-16
→ x = 19
Then,
★ Present age of Nilu = 19 years
★ Present age of Mrs. Jain = (19+27) = 46 years.
Therefore, the present age of Nilu is 19 years and Present age of Mrs. Jain is 46 years.