Question

Mrs. Jain is 27 years older than her daughter Nitu. She will be twice as old as Nitu. Find the present age.

Answer 1

Answer:

Nitu's age= 27 yrs

Mrs. Jain's age= 27+27=54 yrs

Step-by-step explanation:

Nitu's age= 'x' yrs

Mrs. Jain's age= 'x+27' yrs

Acoording.To.Question:

2(x)=x+27

  2x=x+27

2x-x=27

    x=27 yrs

This is the answer to your question.

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Answer 2

Let the present age of Nitu be x years

Therefore the present age of Nitu’s mother = (x + 27) years

So, after 8 years, Nitu’s age = (x + 8)

and Mrs Jain’s age = (x + 27 + 8) = (x + 35) years

⇒ x + 35 = 2(x + 8)

Expanding the brackets, we get

⇒ x + 35 = 2x + 16

Transposing x to RHS and 16 to LHS, we get

⇒ 35 – 16 = 2x – x

⇒ x = 19

So, the present age of Nitu = x = 19 years

And the present age of Nitu’s mother that is Mrs Jain = x+ 27 = 19 + 27

= 46 years

THEREFORE,

Nitu's age = 19 years

Mrs Jain = 46 years