Question

Mrs khanna has jewellery worth Rs 5,50,000. if the value of gold appreciated by 10% in a year, find the original price of the jewellery ( assuming she bought the gold a year back) ?​

Answer 1

Rs 5,00,000

Step-by-step explanation:

How to solve ?

Basically This question is related to Uniform rate of growth. So, just use the formula for solution i.e

$\sf \large{\: A = \: P {(1 + \dfrac{r}{100} )}^{n}}$

here, A = Amount ( Final money)

P = Principal (Initial Money)

r = rate of increase per year

n = no. of years

Given:

P = ?

A = Rs 550000

r = 10%

n = 1 year

Solution:

Let, the principal be x

According to question,

$\sf A\: = P(1 + \frac{r}{100}) {}^{n} \\ \\ \sf 550000 = x \times (1 + \frac{10}{100}) {}^{1} \\ \\ \sf 550000 = x \times \frac{110}{100} \\ \\ \sf \cancel{550000} \: = \: x \: \times \frac{ \cancel{11}}{10} \\ \\ \sf 50000 \times 10 = x \\ \\ \sf \: x = Rs \: 500000$

Therefore, The required answer is Rs 500000.

Answer 2

Answer:

Question:-

Mrs Khanna has a jewellery worth Rs 5,50,000. If the value of gold appreciated by 10% in a year, find the original price of the jewellery [By assumption that she bought the gold a year ago].

Step-by-step explanation:

Let's us do it step - by - step

Given in the question:-

P = ?

S.I = Rs 5,50,000

R = 10%

T = 1 year

Here as the time is 1 year so we can also write the "Rate of interest " as 10% per annum

But we are not going to do such a complicated process let us do this in simple steps

Knowledge required:-

• (P) refers to the principle
• (S.I) refers to the Simple interest
• (R) refers to Rate of interest
• (T) refers to time

Formula to be used in the question

[Principal = 100 × interest

rate × time

Here S.I only refers to interest

Let's find out:-

[ Principal = 100×interest ]

rate × time

=》P = 100× 5,50,500

10% ×1 year

=》 P = 100×5,50,500

110%× 1 year

•°• 110 one zero and 100 one zero will be cut off

=》P= 10×5,50,500

11 % × 1 year

•°• Now, 11 will cut from Rs. 5,50,500

=》 p= 10×50,000

=》p = 5,00,000

•°•Required answer is Rs 5,00,000

Know more!!

• Interest = principal ×rate×time

100

• Principal = 100×interest

rate × time

• Time = 100 × interest

principal ×rate

• Rate of interest = 100 × interest

principal ×time

S.I in Physics is known as standard unit

S.I in maths is known as Simple interest