Question

mt. everest is at a height of 8850 m. its base is at an elevation of 5400 m. the temperature here drops at a rate of 1 digree c. per 100 m. if the temperature at the base is 5 digree c. what is the temperature at the top.

Answer 1

Temperature of drops from 5400 m  = 1 degree per 100 m (given in the question)
height of top peak = 8850 m
temperature at base of Everest  = -5 degree (it is also given in the question)

so,,

height of top peak from the base = 8850 - 5400 = 3450 m
total drops in temperature  = 3450/100 = 34.5 degree

so temperature at top = -5 - 34.5 = -39.5 degree Celsius

-39.5 degree celsisus  is the answer

Answer 2

☆ Answer ☆

$\sf \green{ -39.5°C}$

☆ Solution ☆

$\rightarrow$ Height of My. Everest from its base = 8850-5400

3450 m =

$\rightarrow$ Drop in temperature = 3450/ 100 = 34.5 =

$\rightarrow$ Temperature at the top = -5°C - (34.5) °C

= -39.5°C

$\fbox\red{Hope It Helps}$