Math, asked by avkashtomar1987, 9 months ago

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Answered by Anonymous
16

Answer:

x = -a, -b

Step-by-step explanation:

1/a + 1/b + 1/x = 1/(a + b + x)

1/a + 1/b = 1/(a + b + x) - 1/x

1/a + 1/b = (x - a - b - x)/(ax + bx + x²)

1/a + 1/b = (- a - b)/(x² + ax + bx)

(a + b)/ab = -(a +b)/(x² + ax + bx)

Cross-multiply it

-(a + b)(ab) = (x² + ax + bx)(a + b)

-(a + b)/(a + b) × (ab) = x² + ax + bx

-ab = x² + ax + bx

-ab = x² + x(a + b)

Factorise it

x² + x(a + b) + ab = 0

x² + ax + bx + ab = 0

Take common

x(x + a) + b(x + a) = 0

(x + b)(x + a) = 0

On comparing we get,

x = -b, -a

Answered by jiya91729
1

Answer:

-a,-b are answer dear friend

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