Math, asked by paridhi987, 1 year ago

Mukta had Rs.42.On 4 th jan 2018 ,she saves rs 15 .After this day,every day she saved 12 more rupees than the earlier day.Then including the saving,how much total amount did she have up to 30 th jan 2018?​

Answers

Answered by Anonymous
20

Ello ❤

Your answer is here ▪▪▪▪▪

Solution:

Mukta had Rs. 42.

she saved Rs. 15 on 4 th january 2018

The amount with Mukta on 4 th january 2018

= 42+15

=57 rs.

After 4 th january 2018 , she saved 12 more rupees than the earlier day up to 30 th of January 2018

From 4 th january 2018 , onwards the amount of rupees mukta had on every day is 57,69,81 rs.

This is an A. P

Because difference between two consecutive term is same.

a=57 rs.

d= (69-57) rs.

= 12 rs.

n = 27 days

So,

tn = a+(n-1) d

t27= 57+(27-1) × 12

=57+26×12

=57+312

=369

After that.. .

Sn = n/2(t1+tn)

=27/2(57+369)

=27/2×426

=27×213

=5751 Rs.

Answer: Including the savings up to 30 th january 2018 , Mukta had amount of Rs. 5751 with her.

Hope it helps you Paridhi


paridhi987: Superb answer............❤❤✌
Anonymous: Hehe thx❤
FASHI0NTheQueen: Perfect❤❤❤
Anonymous: thx❤
FASHI0NTheQueen: wello✌
Answered by ItsMeGaYaTri
0

Answer:

Answer is 5751 rupee.. .. .. .. . . . .. . ...

Similar questions