multiple (4a - 3b) (a^2 + b^2 - c^2)
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Answer:
4a(a^2+b^2-c^2)-3b(a^2+b^2-c^2)
(4a-3b) (a^2+b^2-c^2)
Step-by-step explanation:
(4a-3b) (a^2+b^2-c^2)
4a^3+4ab^2-4ac^2-3a^2b-3b^3+3bc^2
4a(a^2+b^2-c^2)-3b(a^2+b^2-c^2)
(4a-3b) (a^2+b^2-c^2)
that's solved
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