Math, asked by vasundharameena78, 1 year ago

multiple (4a - 3b) (a^2 + b^2 - c^2)​

Answers

Answered by sonu8964
1

Answer:

4a(a^2+b^2-c^2)-3b(a^2+b^2-c^2)

(4a-3b) (a^2+b^2-c^2)

Step-by-step explanation:

(4a-3b) (a^2+b^2-c^2)

4a^3+4ab^2-4ac^2-3a^2b-3b^3+3bc^2

4a(a^2+b^2-c^2)-3b(a^2+b^2-c^2)

(4a-3b) (a^2+b^2-c^2)

that's solved

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