multiples of 19 between 57 and 152
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the answer is 6
last term =152
first term=57
common diffference=19
(last term-first term)÷cd+1=no. of terms
(152-57)÷19+1=6
there 4 6 no.s b/w them
last term =152
first term=57
common diffference=19
(last term-first term)÷cd+1=no. of terms
(152-57)÷19+1=6
there 4 6 no.s b/w them
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Answer:
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