Multiply (2x+5y) and (3x-4y)
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Answer:
Step-by-step explanation:
Simplifying
(2x + -5y)(3x + -4y) = 0
Multiply (2x + -5y) * (3x + -4y)
(2x * (3x + -4y) + -5y * (3x + -4y)) = 0
((3x * 2x + -4y * 2x) + -5y * (3x + -4y)) = 0
Reorder the terms:
((-8xy + 6x2) + -5y * (3x + -4y)) = 0
((-8xy + 6x2) + -5y * (3x + -4y)) = 0
(-8xy + 6x2 + (3x * -5y + -4y * -5y)) = 0
(-8xy + 6x2 + (-15xy + 20y2)) = 0
Reorder the terms:
(-8xy + -15xy + 6x2 + 20y2) = 0
Combine like terms: -8xy + -15xy = -23xy
(-23xy + 6x2 + 20y2) = 0
Solving
-23xy + 6x2 + 20y2 = 0
Solving for variable 'x'.
Factor a trinomial.
(2x + -5y)(3x + -4y) = 0
Answered by
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Step-by-step explanation:
(2x+5y) × (3x-4y)
2x+5y×3x-4y
2x×3x+5y-4y
6x+9y
Answer : 6x+9y
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