Math, asked by savitha1536, 5 months ago

Multiply(2x²-3x³)(x³+x²)​

Answers

Answered by Anonymous
3

= −3x^6−x^5+2x^4

Step-by-step explanation:

(2x^2−3x^3)(x^3+x^2)

=(2x^2+−3x^3)(x^3+x^2)

=(2x^2)(x^3)+(2x^2)(x^2)+(−3x^3)(x^3)+(−3x^3)(x^2)

=2x^5+2x^4−3x^6−3x^5

=−3x^6−x^5+2x^4

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