Question

multiply 3x^2y and (2x^3y^3-5x^2y+9xy​

Answer 1

$\huge\underbrace\mathfrak\purple{Solution}$

$3 {x}^{2} y(2 {x}^{3} {y}^{3} - 5 {x}^{2} y + 9xy) \\ \\ = ( 3 \times 2) {x}^{2 + 3} {y}^{1 + 3} - (3 \times {5}){x}^{2 + 2} \\ {y}^{1 + 1} + (9 \times 3) {x}^{2 + 1} {y}^{1 + 1} \\ \\ = 6 {x}^{5} {y}^{4} - 15 {x}^{4} {y}^{2} + 27 {x}^{3} {y}^{2}$

Answer 2

$\Large\bf\pink{Question:}$

$\bf Multiply : \\ \bf {3x}^{2} y \: \: \: and \: \: \: (2x^{3}{y}^{3} - {5x}^{2}y + 9xy)$

$\Large\bf\pink{Answer:}$

$\tt ( {3x}^{2} y)(2 {x}^{3} y^{3} - {5x}^{2} y + 9xy) \\ \tt \longrightarrow (3 {x}^{2} y \times 2x^{3}y^{3} ) + ( {3x}^{2} y \times - 5 {x}^{2} y) + ( {3x}^{2} y \times 9xy) \\ \tt \longrightarrow (6x^{2 + 3}y^{1 + 3}) + ( - 15 {x}^{2 + 2}y^{2} ) + (27 {x}^{2 + 1} {y}^{2} ) \\ \tt \longrightarrow ( {6x}^{5} y^{4} ) + ( - 15x^{4} {y}^{2} ) + (27 {x}^{3} {y}^{2} ) \\ \tt \longrightarrow { \pink{ \underline{ \boxed{ \bf{6x}^{5} {y}^{4} - 15 {x}^{4} {y}^{2} + {27x}^{3} {y}^{2} }}}}$

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