Math, asked by tripathiyuvraj2006, 6 months ago

Multiply (3x^4-x^2+6x-7) by (x^2-3x+4)

Answers

Answered by akashpatelngl

5

Answer:

3x^6 - 9x^5 + 11x^4 + 9x^3 - 29x^2 + 45x - 28

Step-by-step explanation:

(3x^4-x^2+6x-7) * (x^2-3x+4)

= 3x^6 - x^4 + 6x^3 - 7x^2 - 9x^5 + 3x^3 - 18x^2 + 21x + 12x^4 - 4x^2 + 24x - 28

= 3x^6 - 9x^5 + 11x^4 + 9x^3 - 29x^2 + 45x - 28

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