Math, asked by Tooba55, 1 year ago

Multiply:- (4x²+3y) by (3x²-4y) and verify the result for x=1, y=2​

Answers

Answered by Anonymous
33

Answer:

(4x^{2}  + 3y) \times (3x^{2}-4y) \\ 12x ^4 -16x^{2} y + 9x ^{2} y - 12y ^{2}  \\ 12x ^4 - 7x ^{2}y - 12y  ^{2}    \\ x = 1 \:  \:  \:  \:  \: y = 2 \: se \\ 12(1)^4 -7(1) ^{2} (2) - 12(2) ^{2}  \\ 12 - 14 - 48 =  - 50

Answered by jai96666
11

Answer:

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