Math, asked by ameghabiju1, 3 days ago

Multiply (6a²-5a+10) by (4-3a?)​

Answers

Answered by preeti353615
0

Answer:

Multiply (6a²-5a+10) by (4-3a)​ we get (18a^3 - 39a^2 + 50a - 40)

Step-by-step explanation:

Multiply (6a²-5a+10) by (4-3a)​

(4-3a)​ × (6a²-5a+10)

= 4 (6a²-5a+10) - 3a (6a²-5a+10)

= 4 (6a²) - 4(5a) + 4(10) - 3a(6a²)+ 3a (5a)- 3a(10)

= 24a^2 - 20a + 40 - 18a^3 + 15a^2 - 30a

Rearrange similar terms

=- 18a^3 + 24a^2  + 15a^2 - 20a   - 30a + 40\\= - 18a^3 + (24 + 15)a^2 - (20 +30)a + 40\\= -18a^3 + 39a^2 - 50a + 40\\= 18a^3 - 39a^2 + 50a - 40

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