Math, asked by deepadubey818, 19 days ago

Multiply (6x^3 - 5x^2 + 4x) by (x^2 + 7x - 1)​

Answers

Answered by Splendidgirl
4

( 6{x}^{3}   - 5 {x}^{2}  + 4x )\: ( {x}^{2}  + 7x - 1) \\ \\  6 {x}^{3} ( {x}^{2}  + 7x - 1) - 5 {x}^{2} ( {x}^{2}  + 7x - 1) \\  + 4x( {x}^{2}  + 7x - 1) \\  \\  {6x}^{5}  + 42 {x}^{4}  - 6 {x}^{3}  - 5 {x}^{4}  - 35 {x}^{3}  + 5 {x}^{2}  \\  + 4 {x}^{3}  + 28 {x}^{2}  - 4x \\  \\ 6 {x}^{5}  + 37 {x}^{4}  - 37 {x}^{3}  + 33 {x}^{2}  - 4x

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