Question

Multiply (6x2 – 5x + 3) by (3x2 + 7x – 3)

Answer 1

Step-by-step explanation:

(18x'4+42x'3-18x'2)-(15x'3+35x'2-15x)+(9x'2+21x-9)

18x'4+27x'3-44x'2+36x-9

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Answer 2

The product of (6x2 – 5x + 3) by (3x2 + 7x – 3) is $18x^4 + 27x^3 - 34x^2 + 6x -9$

To multiply the two polynomials (6x2 – 5x + 3) by (3x2 + 7x – 3),

we can use the distributive property of multiplication over addition, also known as the FOIL method (First, Outside, Inside, Last).

(6x2 – 5x + 3) * (3x2 + 7x – 3)

= (6x2 * 3x2) + (6x2 * 7x) + (6x2 * -3) + (-5x * 3x2) + (-5x * 7x) + (-5x * -3) + (3 * 3x2) + (3 * 7x) + (3 * -3)

= $18x^4 + 42x^3 - 18x^2 - 15x^3 - 35x^2 + 15x + 9x^2 + 21x - 9$

To combine like terms,

= 1$8x^4 + 27x^3 - 34x^2 + 6x -9$

So the product of (6x2 – 5x + 3) by (3x2 + 7x – 3) is $18x^4 + 27x^3 - 34x^2 + 6x -9$

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