Multiply (a – 1) (a + 1) (a2
+ 1)
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3
Answer:
Solution:
_______________________
We know the algebraic identity:
(x+y)(x-y) = x² - y²
________________________
Here ,
(a+1/a)(a-1/a)(a²+1/a²)(a⁴+1/a⁴)
=[(a+1/a)(a-1/a)](a²+1/a²)(a⁴+1/a⁴)
=[a²-(1/a)²](a²+1/a²)(a⁴+1/a⁴)
=[(a²-1/a²)(a²+1/a²)](a⁴+1/a⁴)
= [(a²)²-(1/a²)²](a⁴+1/a⁴)
= (a⁴-1/a⁴)(a⁴+1/a⁴)
= (a⁴)²-(1/a⁴)²
= a^{8}-\frac{1}{a^{8}}a 8 −a 81
Therefore,
(a+1/a)(a-1/a)(a²+1/a²)(a⁴+1/a⁴) = a^{8}-\frac{1}{a^{8}}a
8 −a 81
•••••
Step-by-step explanation:
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0
Answer:
here's ur answer hope this helps u
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