Multiply a² + a - 3 by 2a² - a +5
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We are trying to find a3−2a2−2a2−1a3 given that a−1a=2 .
Some quick manipulation before we start that will help:
First, a−1a=2
Next,
(a−1a)2
=a2−2(a)(1a)+1a2
=a2+1a2−2
Another way of expressing the expression squared is (a−1a)2=22=4
So a2+1a2=6 . Remember this.
And:
(a−1a)3
=a3−3(a2)(1a)+3(a)(1a2)−1a3
=a3−3a+3a−1a3
=a3−3(a−1a)−1a3
=a3−1a3−6
Similarly , we can also say that (a−1a)3=23=8 .
So (a−1a)3=14
With that, our solution becomes easier.
a3−2a2−2a2−1a3
=(a3−1a3)−2(a2+1a2)
=14−2(6)
=2
your answer is 2
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