Math, asked by 73737username, 2 months ago

multiply following and verify the result for X equal to 2 y equal to 1 and z equal to 3 ​

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Answers

Answered by mrgoodb62
0

Answer:

x

3

y

3

×(3x−15y)

=

3

2

x

3

y

3

⋅3x−

3

2

x

3

y

3

⋅15y

=2x

4

y

3

−10x

3

y

4

Now, for x=2,y=−1, we have

L.H.S.-

3

2

x

3

y

3

×(3x−15y)

=

3

2

(2)

3

(−1)

3

×(3⋅2−15⋅(−1))

=

3

2

⋅8⋅(−1)×(6+15)

=(−

3

16

)×21

=−112

R.H.S.-

2x

4

y

3

−10x

3

y

4

=2(2)

4

(−1)

3

−10(2)

3

(−1)

4

=2⋅16⋅(−1)−10⋅8⋅1

=−32−80

=−112

∵ L.H.S. = R.H.S.

Hence verified.

Answered by IxIitzurshizukaIxI
3

Answer:

32x3y3×(3x−15y)

=32x3y3⋅3x−32x3y3⋅15y

=2x4y3−10x3y4

Now, for x=2,y=−1, we have

L.H.S.-

32x3y3×(3x−15y)

=32(2)3(−1)3×(3⋅2−15⋅(−1))

=32⋅8⋅(−1)×(6+15)

=(−316)×21

=−112

R.H.S.-

2x4y3−10x3y4

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