Multiply :
(i) 9x^3 (4+3x)
(ii) (x+6) (x^2+3y) + 24 ; [For x = -1 , y = 1]
(iii) (x^2-6) (x-6) - 36 ; [For x = -2]
Plz Answer....
I need Correct Answer Then Only I mark [Brainleist Answer]
Reward : 20 Points..
Plz Answer....
Answers
Answered by
0
Answer:
In the figure, AB is parallel to PQ.
a) If area of AAPB = 80 sq.cm, then find area of A AQB
b) Write another one pair of triangle with same area?
Answered by
1
Answer:
9x³( 4+3x) = 9x³(4) + 9x³(3x)
= 36x³ + 27 x⁴
(x+6)(x²+3y) +24 = x(x²+3y)+6(x²+3y)+24
= x³+3xy+6x²+18y+24
substitute x=-1and y =1
then (x+6)(x²+3y)+24 = (-1)³+3(-1)(1)+6(-1)²+18(1)+24
= -1-3+6+18+24
=-4+48
= 44
(x²-6)(x-6)-36= x²(x-6)-6(x-6)-36
= x³-6x²-6x+36-36
= x³-6x²-6x
substitute x= -2
= (-2)³-6(-2)²-6(-2)
= -8-6*4+12
= -8-24+12
= -32+12
= -20
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