Math, asked by hero6892, 1 year ago

Multiply the Bionomials (y-8) and (3y-4) ​

Answers

Answered by Anonymous
80

(y-8)(3y-4).

=y(3y - 4) -8(3y - 4 ).

= 3y^2 - 4y - 24y + 32.

= 3y^2-28y+32.


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Answered by Bhasksr
38

ANSWER:

(y - 8) \times (3y - 4) \\  =  {3y}^{2}  - 4y - 24y + 32 \\  =  {3y}^{2}  - 28y + 32 \\

HOPE IT HELPED YOU☺

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