multiply the irrational number
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6√15 × 4√3
= (6 × 4)(√15 × √3)
We know that,
√a × √b = √(a×b) = √ab
so, we will solve this equation by this formula,
= 24√(15×3)
we know that, √15 can be written as => √5 × √3,
= 24 [ √5 × √3 × √3 ]
= 24 ( √5 × 3 )
= 24 × 3√5
= 72√5 ....answer!
rakeshmohata:
edit it..dear
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6
6√15 ×4√3
Now,
6√15 × 4√3
= (6×4) × (√15×√3)
[As we know that √a × √b = √AB.]
= 24×√45
= 24√45
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