Math, asked by santoshnaidu254, 5 days ago

Multiply (x+y) and (3x+4y) to each other and verify the product for the following values: Number (1 ). x=1, y=0​

Answers

Answered by bvchratnakumari1988
4

Answer:

Correct option is

C

(5,7)

3x+4y=43 ----- (1)

−2x+3y=11 ----- (2)

First use formula for cross multiplication method:

b

1

c

2

−b

2

c

1

x

=

c

1

a

2

−a

1

c

2

y

=

a

2

b

2

−a

2

b

1

−1

So, from equation (1) and (2) we can write the value of a, b and c.

4×11−3×43

x

=

43×(−2)−3×11

y

=

3×3−(−2)×4

−1

44−129

x

=

−86−33

y

=

9+8

−1

−85

x

=

−119

y

=

17

−1

−85

x

=

17

−1

x=

17

85

=5

−119

y

=

17

−1

y=

17

119

=7

The solution is (5,7)

Answered by nsdivyausundhar
0

Answer:

multiply (x+y) and (3x+4y) to each other and verify the product for the following values

x=1 y=0

Step-by-step explanation:

3(1)+4(0)=3

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