Question

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Answer 1

Answer:

8 times

Understanding the códe...

• initially, count = 1
• now while loop runs until count<=15
• Each iteration, '*‎*‎*' is printed on the condition that count is odd number (odd numbers have remainder 1) otherwise, "+++++" is printed.
• count is incremented.

Solution(with explaination):

• when count=1,
• while loop begins at the condition that could is less than or equal to 15
• 1<=15, condition true.
• Is 1%2==1? Yes *‎3 asterisk(*) is printed.
• count=2
• is 2<=15? Yes
• 2%2==1? No, condition false, "+++‎‎+‎+" is printed.
• count becomes 3
• 3<=15? Yes
• 3%2==1? Yes, *‎*‎* is printed
• ...and so on till count becomes 15
• when count becomes 16, loop terminates.

Output will be like...

*‎*‎*

+++‎++

*‎*‎*

+++‎++

*‎*‎*

++‎+++

*‎*‎*

+++‎++

*‎*‎*

++‎+++

*‎*‎*

+++‎++

*‎*‎*

++‎+++

*‎*‎*

As we can see here, *‎*‎* is printed 8 times, so answer is 8.