Multiplying
the given polynomials
2y+2;y2 _2y3 + 3y
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Step-by-step explanation:
(2y+1)×(y 2 −2y 3+3y)
=2y(y2−2y3+3y)+1(y 2−2y3+3y)
=2y 3−4y 4+6y 2+y 2−2y 3+3y
=−4y 4+2y 3−2y 3+6y 2+y2+3y
=−4y 4+7y 2+3y
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