Math, asked by NerfBoy78, 3 months ago

multipy: 1=(x-a) (x+3b) 2=(3x+y-8)

I need the solution​

Answers

Answered by nerd57
0

Answer:

(x square +3xb−ax−3ab)(3x+y−8)

x square(3x+y−8)+3xb(3x+y−8)−ax(3x+y−8)−3ab(3x+y−8)

3x  cube +x  square  y−8x  square +3xb(3x+y−8)−ax(3x+y−8)−3ab(3x+y−8)

3x  cube +x  square  y−8x  square 9x  square b+3xby−24xb−ax (3x+y−8) −3ab(3x+y−8)

3x  

3

+x  

2

y−8x  

2

+9x  

2

b+3xby−24xb−(3ax  

2

+axy−8ax)−3ab(3x+y−8)

3x  

3

+x  

2

y−8x  

2

+9x  

2

b+3xby−24xb−(3ax  

2

+axy−8ax)−(9abx+3aby−24ab)

3x  

3

+x  

2

y−8x  

2

+9x  

2

b+3xby−24xb−3ax  

2

−axy+8ax−9abx−3aby+24ab

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