Multipy -8/21 x²y³ by -17/16
xy^2 and verify your result for x = 3 and y = 2.
Answers
Answer:
hero ki abhishek nigam
Step-by-step explanation:
On Friday, Lisa spent five hours to complete her mathematics homework, science homework and to draw a picture. She spends one-fifth of the time doing her mathematics homework and two-fifth of the time doing science homework and the rest of the time to draw a picture.
What fraction of the time did she spend to do mathematics and science homework together? *
(a) 1/5
(b) 2/5
(c) 3/5
(d) 4/5
2. What fraction of the time did she spend to draw the picture? *
(a) 1/5
(b) 2/5
(c) 3/5
(d) 4/5
3.How much time did she use to complete her science homework?
(a) 1 Hour
(b) 2 Hours
(c) 3 Hours
(d) 4 Hours
How much time did she use to complete her mathematics homework and to draw a picture? *
(a) 1 Hour
(b) 2 Hours
(c) 3 Hours
(d) 4 Hours
Answer:
To prove: x3−y3=(x−y)(x2+xy+y2)
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS Hence proved.
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS Hence proved.Yes, we can call it as an identity: For example:
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS Hence proved.Yes, we can call it as an identity: For example:Let us take x=2 and y=1 in x3−y3=(x−y)(x2+xy+y2) then the LHS and RHS will be equal as shown below:
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS Hence proved.Yes, we can call it as an identity: For example:Let us take x=2 and y=1 in x3−y3=(x−y)(x2+xy+y2) then the LHS and RHS will be equal as shown below:23−13=7 and
To prove: x3−y3=(x−y)(x2+xy+y2)Consider the right hand side (RHS) and expand it as follows:(x−y)(x2+xy+y2)=x3+x2y+xy2−yx2−xy2−y3=(x3−y3)+(x2y+xy2+x2y−xy2)=x3−y3=LHS Hence proved.Yes, we can call it as an identity: For example:Let us take x=2 and y=1 in x3−y3=(x−y)(x2+xy+y2) then the LHS and RHS will be equal as shown below:23−13=7 and (2−1)(22+(2×1)+12)=1(5+2)=1×7