Murray’s father deposited $6,000 of his savings into two accounts. One account earns 1.5 percent interest, and the other account earns 2.5 percent interest. At the end the year, the interest in the account that earned 2.5 percent was $110.00 more than the other account. Which system represents the amounts of money, x and y, that was put into each account?
x + y = 6,000. 0.025 x + 0.015 y = 110.
x + y = 6,000. 0.25 x + 0.15 y = 110.
x + y = 6,000. 0.025 x minus 0.015 y = 110.
x + y = 6,000. 2.5 x minus 1.5 y = 110.
Answers
Answer:
none of these because
si = p*r*t divided by 100
Step-by-step explanation:
so
answer is
none of these
as expression of equation is different.
Answer:
The final answer is ( 1.5x - 2.5x ) / 100 = 110 and none of these options.
Step-by-step explanation:
Given,
Total amount in both accounts = 6000
Let x be the account number 1 and y be account number 2, Then
Total Amount = x + y = 6000
We also know that Account 1 has an interest of 1.5% and account 2 has an interest of 2.5%, Let this be r1, r2 respectively.
Time period = 1 year
Simple Interest = ( p * r * t ) / 100
Also given, Interest in the second account was greater than the first by a margin of 110 then
1.5x / 100 = 2.5x / 100 + 110
By rearranging we get,
( 1.5x - 2.5x ) / 100 = 110
The answer is none of these.
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