Math, asked by zukiiiii, 4 months ago

Jane has 75 books . 18 of the books are comic books. The rest of the books are novels.
a. What percent age of her books are comic books?
b. What percentage of her books are novels?

Answers

Answered by malaymandal480
2

Answer:

comic books=18×100/75 =24%

novels are=(75-18) ×100/75=57×100/75=76%

Answered by ravan2009
6

Question:

Jane has 75 books . 18 of the books are comic books. The rest of the books are novels.

a. What percent age of her books are comic books?

b. What percentage of her books are novels?

Given:

Jane has a total of 75 books , out of which 18 are Comics and the rest are Novels

Number of Novels = 75 - 18 = 57

To Find:

a. What percentage of her books are comic books?

b. What percentage of her books are novels?

Solution:

Percentage of her books are comic books =

\frac{18}{75}\times100\\\\\\\frac{18}{3}\times4\\\\\\\frac{6}{1}\times4\\\\\\6\times4\\\\\\=24\%

Percentage of her books are novels =

\frac{57}{75}\times100\\\\\\\frac{57}{3}\times4\\\\\\\frac{19}{1}\times4\\\\\\6\times4\\\\\\=76\%

Percentage of her books are novels = Total Percentage  -  Percentage of her books are comic books

100\%-24\%\\\\\\=76\%

Answer:

Answer 24% percent of her books are Comics and 76% of her books are Novels

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