Question

mx^2 - 8x + 4 = 0 find the values of m​

Answer 1

Answer:

is there any value of D(discriminant) either equal , more or less in terms of 0.

Step-by-step explanation:

If it is there, pls write in comments. I will give you answer there.

Answer 2

mx² - 8x + 4 = 0

if b² − 4ac>0, then the roots are real and distinct

if b² − 4ac=0, then the roots are real and equal

if b² − 4ac<0, then the roots are imaginary

b² - 4ac = (-8)² - 4×m×4 = 64 - 16m = 16(4 - m)

16(4 - m) > 0

4 > m

16(4 - m) = 0

m = 4

16(4 - m) < 0

4 < m

Above are the values of m. Each value will determine the roots of quadratic equation.

Check your question whether the nature of roots is given.